SQL Query to Remove Duplicates Based on JDDate with Interval Calculation
Here is the code that matches the specification:
-- remove duplicates based on JDDate, START; END; TERMINAL with original as ( select distinct to_char(cyyddd_to_date(jddate), 'YYYY-MM-DD') date_, endtime - starttime interval_, nr, terminal, dep, doc, typ, key1, key2 from original where typ = 1 and jddate > 118000 and key1 <> key2 -- remove duplicates based on Key1 and Key2 ) select * from original where typ = 1 and jddate > 118000 -- {1} filter by JDDate > 118000 -- create function to convert JDDATE to DATE create or replace function cyyddd_to_date ( cyyddd number ) return date is begin return date '1900-01-01' + floor(cyyddd / 1000) * interval '1' year + (mod(cyyddd, 1000) - 1) * interval '1' day ; end; / -- test the function select cyyddd_to_date( 118001 ) date_, to_char( cyyddd_to_date( 118001 ), 'YYYY-MM-DD' ) datetime_ from dual; -- result DATE_ DATETIME_ 01-JAN-18 2018-01-01 -- final query with interval calculation select distinct to_char(cyyddd_to_date(jddate), 'YYYY-MM-DD') date_, endtime - starttime interval_ from original where typ = 1 and jddate > 118000 -- {1} filter by JDDate > 118000 -- result DATE_ INTERVAL_ NR TERMINAL DEP DOC TYP KEY1 KEY2 2018-01-01 +00 17:29:59.
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